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8p^2-45p+25=0
a = 8; b = -45; c = +25;
Δ = b2-4ac
Δ = -452-4·8·25
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-35}{2*8}=\frac{10}{16} =5/8 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+35}{2*8}=\frac{80}{16} =5 $
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